Module 4A
Complex Variables: Differentiation
Let f(x) be a small valued function of the variable then

Provided that the limit exists and is independent of the path along which
Example. If .
Solution.






Along real axis,


Along imaginary axis



(1) Prove that f(z)= has no derivative
Sol We have


Now if is real then
and we have

If we let approach to zero along y=mx so
then




Which implies that there are infinitely many values of the above limit depending upon the choice of m? Thus it is clear that has no derivative at the origin
(2) Test the differentiability of the function for
and f(0)=0
Solution


Since and f(0)=0
Thus
For testing the differentiability of f(z) at z=0 let us first take z approaching 0 along the x axis then


But if we let z approach 0 along the line y=x then


=-1
The two limit are not equal we conclude f(z) is not differentiable at the origin.
If where (x,y)=(0,0)
3. Prove that
Answer








Again






Theorem; The necessary condition for a function to be analytic at all the points in a region R are
(ii)
Provided,
Proof;\
Let be an analytic function in region R.





Along real axis




Along imaginary axis




From equation (2) and (3)

Equating real and imaginary parts

This is called Cauchy Riemann Equation
A function is said to be analytic at a point
if f is differentiable not only at
but an every point of some neighborhood at
.
Example, Prove that the function is an analytical function.
Solution. Let =u+iv
Let =u and
=v



Hence e-R-Equation satisfied.
Prove that
Answer Given that



Since

V=2xy

Now






But



Hence
State and prove sufficient condition for analytic functions
Answer Statement – The sufficient condition for a function to be analytic at all points in a region R are
1
2 are continuous function of x and y in region R.
Proof :- Let f(z) be a simple valued function having at each point in the region R. Then Cauchy-Reimann equation are satisfied by Taylor’s Theorem




Ignoring the terms of second power and higher power

We know C-R equation

Replacing
Respectively in (1) we get







Show that is analytic at
Ans The function f(z) is analytic at if the function
is analytic at z=0
Since

Now is differentiable at z=0 and at all points in its neighbourhood Hence the function
is analytic at z=0 and in turn f(z) is analytic at
Any function which satisfies the Laplace equation is known as harmonic function.
i.e.
Example; Prove that is Harmonic Function.
Solution.



Hence function is harmonic.
Prove that is harmonic function
Ans Given



Thus
Which shows that u is satisfies Laplace equation
Prove that is harmonic function
Ans











Which satisfies the Laplace equation. Hence the given function is harmonic
If
Then function is harmonic conjugate.
A function is analytic in a domain if it is analytical at every point of the domain.
Position on exponential Trigonometric logarithm
Example; Prove that function is analytic function.
Solution. Real and Imaginary parts of are










If,
On differentiating u,v we get



Again differentiating



Hence e-R-Equation satisfies.
Properties
(i) Polynomials rational function are entire.
(ii) A differentiable function is always continuous but converse is not true.
Ques Determine P such that the function analytic
Ans

Hence





f(z) is analytic Cauchy Riemann should be satisfied that is


And
P=-1
Question If and
is an analytic function of z=x+iy find f(z) in terms of z by Milne Thomas method
Answer f(z) is analytic since f is analytic
Let f’=u+iv
Then

Since u.v satisfy C-R conditions

Integrating w.r.t y we get

Differentiation v w.r.t x and using second C-R condition we get


Thus V(x,y)=6xy+4x+
Where is an arbitrary constant Then

Applying Milne Thomas method replace x by z and y by 0 we get

Integrating w.r.t z we get

Where is an arbitrary constant since f(1+ i)=0
We get


Thus
If the sense of the relation as well as magnitude of the angle is preserved the transformation is said to be conformal.
Example; Find the conformal transformation of .
Answer. Let



Theorem If W=f(z) represents a conformal transformation of a domain D in the z-plane into a domain D of the W plane then f(z) is an analytic function of z in D.
Proof We have u+iv=u(x,y)+iv(x,y)
So that u=u(x,y) and v=v(x,y)
Let ds and denote elementary arc length in the z-plane and w-plane respectively Then

Now
Hence
Or
Where

Now is independent of direction if

Where h depends on x and y only and is not zero. Thus the conditions for an isogonal transformation

And
The equation are satisfied if we get

Then substituting these values in 2 we get



Taking i.e.

Also
Hence
Similarly i.e.

The equation (4) are the well known Cauchy -Reimann
Conformal mapping
Show that the mapping is conformal in the whole of the z plane.
Ans Let z=x+iy

Then


Consider the mapping of the straight line x=a in z plane the w plane which gives which is a circle in the w plane in the anticlockwise direction similarly the straight line y=b is mapped into
which is a radius vector in the w plane.
The angle between the line x=a and y=b in the z plane is a right angle. The corresponding angle in the w plane between the circle e = constant and the radius vector is also a right angle which establishes that the mapping
is conformal.

Equation (1) is called bilinear transformation
If then
i.e. transformation is conformal
From (1)
This is called bilinear except
Properties
(i) A bilinear transformation maps circles inti circles.
(ii) A bilinear transformation preserves cross ratio of four points.
Example, Find the fixed points and normal points of
Answer. The final points are b



is only fixed point
This transformation is parabolic.
Normal form



Every mobius transformation maps circles or straight line into circles or straight line
Proof : The equation of circle in the z plane may be written as

Where A, C are real and B is a complex constant such that If A=0 then (1) represents a straight line
Let
Be any bilinear transformation. Then transform of (1) under (2) is

Or
Or
Which is of the form

Where


It is evident that of w and
are conjugate complex number
Further



Theorem Every bilinear transformation with two finite fixed points can be part in the form

Proof Consider any bilinear transformation with as fixed points and suppose it transforms a point Y into the point
. Then the points
are mapped into the points
respectively since cross ratio is preserved under a bilinear transformed we have



Which is of the form

TEXTBOOKS/REFERENCES:
- ERWIN KREYSZIG, ADVANCED ENGINEERING MATHEMATICS, 9TH EDITION, JOHN WILEY & SONS, 2006.
- J. W. BROWN AND R. V. CHURCHILL, COMPLEX VARIABLES AND APPLICATIONS, 7TH ED., MC- GRAW HILL, 2004.
- VEERARAJAN T., ENGINEERING MATHEMATICS FOR FIRST YEAR, TATA MCGRAW-HILL, NEW DELHI, 2008.
- N.P. BALI AND MANISH GOYAL, A TEXT BOOK OF ENGINEERING MATHEMATICS, LAXMI PUBLICATIONS, REPRINT, 2010.
- B.S. GREWAL, HIGHER ENGINEERING MATHEMATICS, KHANNA PUBLISHERS, 35TH EDITION, 2000.