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M2


Module 4A


Complex Variables: Differentiation


Let f(x) be a small valued function of the variable then

Provided that the limit exists and is independent of the path along which

Example. If .

Solution.

Along real axis,

Along imaginary axis

 

(1)  Prove that f(z)= has no derivative

Sol    We have

Now if is real then and we have

If we let approach to zero along y=mx so then

Which implies that there are infinitely many values of the above limit depending upon the choice of m? Thus it is clear that has no derivative at the origin

 

(2)  Test the differentiability of the function for and f(0)=0

Solution

Since and f(0)=0

Thus

For testing the differentiability of f(z) at z=0 let us first take z approaching 0 along the x axis then

But if we let z approach 0 along the line y=x then

=-1

The two limit are not equal we conclude f(z) is not differentiable at the origin.

If   where   (x,y)=(0,0)

 

3. Prove that

Answer 

Again             

 


Theorem; The necessary condition for a function to be analytic at all the points in a region R are

         (ii)

Provided,

Proof;\

Let be an analytic function in region R.

Along real axis

Along imaginary axis

From equation (2) and (3)

Equating real and imaginary parts

This is called Cauchy Riemann Equation


A function is said to be analytic at a point if f is differentiable not only at but an every point of some neighborhood at .

Example, Prove that the function is an analytical function.

Solution. Let =u+iv

Let =u and =v

Hence e-R-Equation satisfied.

 

Prove that

Answer Given that

Since      

V=2xy

Now

But                                      

Hence 

 

State and prove sufficient condition for analytic functions

Answer  Statement – The sufficient condition for a function to be analytic at all points in a region R are

1                  

2            are continuous function of x and y in region R.

Proof :-  Let f(z) be a simple valued function having      at each point in the region R. Then Cauchy-Reimann equation are satisfied by Taylor’s Theorem

Ignoring the terms of second power and higher power

We know C-R equation

Replacing

Respectively in (1) we get

 

Show that is analytic at

Ans   The function f(z) is analytic at if the function is analytic at z=0

Since

Now is differentiable at z=0 and at all points in its neighbourhood Hence the function is analytic at z=0 and in turn f(z) is analytic at

 


Any function which satisfies the Laplace equation is known as harmonic function.

i.e.

Example; Prove that is Harmonic Function.

Solution.

Hence function is harmonic.

 

Prove that is harmonic function

Ans   Given 

Thus  

Which shows that u is satisfies Laplace equation

 

Prove that is harmonic function

Ans  

Which satisfies the Laplace equation. Hence the given function is harmonic

 


If

Then function is harmonic conjugate.

 


A function is analytic in a domain if it is analytical at every point of the domain.

Position on exponential Trigonometric logarithm

Example; Prove that function is analytic function.

Solution. Real and Imaginary parts of are

If,

On differentiating u,v we get

Again differentiating

Hence e-R-Equation satisfies.

Properties

(i)                Polynomials rational function are entire.

(ii)              A differentiable function is always continuous but converse is not true.

 

Ques  Determine P such that the function analytic

Ans    

Hence  

f(z) is analytic Cauchy Riemann should be satisfied that is

And                            

P=-1

 

Question      If and is an analytic function of z=x+iy find f(z) in terms of z by Milne Thomas method

Answer  f(z) is analytic since f is analytic

Let   f’=u+iv

Then

Since u.v satisfy C-R conditions

Integrating w.r.t y we get

Differentiation v w.r.t x and using second C-R condition we get

Thus V(x,y)=6xy+4x+

Where is an arbitrary constant Then

Applying Milne Thomas method replace x by z and y by 0 we get

Integrating w.r.t z we get

Where is an arbitrary constant since f(1+ i)=0

We get

Thus

 


If the sense of the relation as well as magnitude of the angle is preserved the transformation is said to be conformal.

Example; Find the conformal transformation of .

Answer. Let

 

Theorem  If W=f(z) represents a conformal transformation of a domain D in the z-plane into a domain D of the W plane then f(z) is an analytic function of z in D.

Proof   We have u+iv=u(x,y)+iv(x,y)

So that u=u(x,y)  and v=v(x,y)

Let ds and denote elementary arc length in the z-plane and w-plane respectively Then

Now 

Hence 

Or

Where  

Now is independent of direction if

Where h depends on x and y only and is not zero. Thus the conditions for an isogonal transformation

And                     

The equation are satisfied if we get

Then substituting these values in 2 we get

Taking   i.e.

Also   

Hence  

Similarly      i.e. 

The equation (4) are the well known Cauchy -Reimann

Conformal mapping

Show that the mapping is conformal in the whole of the z plane.

Ans   Let z=x+iy

Then       

Consider the mapping of the straight line x=a in z plane the w plane which gives which is a circle in the w plane in the anticlockwise direction similarly the straight line y=b is mapped into which is a radius vector in the w plane.

The angle between the line x=a and y=b in the z plane is a right angle. The corresponding angle in the w plane between the circle e = constant and the radius vector is also a right angle which establishes that the mapping is conformal.


Equation (1) is called bilinear transformation

If then

i.e. transformation is conformal

From (1)

This is called bilinear except

Properties

(i)                A bilinear transformation maps circles inti circles.

(ii)              A bilinear transformation preserves cross ratio of four points.

Example, Find the fixed points and normal points of

Answer. The final points are b

is only fixed point

This transformation is parabolic.

Normal form

 

Every mobius transformation maps circles or straight line into circles or straight line

Proof :  The equation of circle in the z plane may be written as

Where A, C are real and B is a complex constant such that   If A=0 then (1) represents a straight line

Let   

Be any bilinear transformation. Then transform of (1) under (2) is

Or             

Or  

Which is of the form

Where   

It is evident that of w and are conjugate complex number

Further

Theorem  Every bilinear transformation with two finite fixed points can be part in the form

Proof    Consider any bilinear transformation with as fixed points and suppose it transforms a point Y into the point . Then the points are mapped into the points respectively since cross ratio is preserved under a bilinear transformed we have

Which is of the form

 

TEXTBOOKS/REFERENCES:

  1. ERWIN KREYSZIG, ADVANCED ENGINEERING MATHEMATICS, 9TH EDITION, JOHN WILEY & SONS, 2006.
  2. J. W. BROWN AND R. V. CHURCHILL, COMPLEX VARIABLES AND APPLICATIONS, 7TH ED., MC- GRAW HILL, 2004.
  3. VEERARAJAN T., ENGINEERING MATHEMATICS FOR FIRST YEAR, TATA MCGRAW-HILL, NEW DELHI, 2008.
  4. N.P. BALI AND MANISH GOYAL, A TEXT BOOK OF ENGINEERING MATHEMATICS, LAXMI PUBLICATIONS, REPRINT, 2010.
  5. B.S. GREWAL, HIGHER ENGINEERING MATHEMATICS, KHANNA PUBLISHERS, 35TH EDITION, 2000.

 


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