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UNIT 5


AVERAGES


 

Mean

  • The mean is the arithmetic average, also called as arithmetic mean.
  • Mean is very simple to calculate and is most commonly used measure of the center of data.
  • Means is calculated by adding up all the values and divided by the number of observation.

Computation of sample mean

If X1, X2, ………………Xn are data values then arithmetic mean is given by

Computation of the mean for ungrouped data

 

Example 1 – The marks obtained in 10 class test are 25, 10, 15, 30, 35

The mean =   X    = 25+10+15+30+35   = 115   =23

5                5

Analysis – The average performance of 5 students is 23. The implication is that students who got below 23 did not perform well. The students who got above 23 performed well in exam.

Example 2 – Find the mean

Xi

9

10

11

12

13

14

15

Freq (Fi)

2

5

12

17

14

6

3

 

Xi

Freq (Fi)

XiFi

9

2

18

10

5

50

11

12

132

12

17

204

13

14

182

14

6

84

15

3

45

 

Fi = 59

XiFi= 715

 

 

 

Then, N = ∑ fi = 59, and ∑fi Xi=715

X    = 715/59 = 12.11

 

Mean for grouped data/ Weighted Arithmetic Mean

Grouped data are the data that are arranged in a frequency distribution

Frequency distribution is the arrangement of scores according to category of classes including the frequency.

Frequency is the number of observations falling in a category

The formula in solving the mean for grouped data is called midpoint method. The formula is

Where, X      = Mean

Xm = midpoint of each class or category

f = frequency in each class or category

∑f Xm = summation of the product of fXm

Example  3 – the following data represent the income distribution of 100 families. Calculate mean income of 100 families?

Income

30-40

40-50

50-60

60-70

70-80

80-90

90-100

No. Of families

8

12

25

22

16

11

6

 

Solution:

Income

No. Of families

Xm (Mid point)

FXm

30-40

8

35

280

40-50

12

34

408

50-60

25

55

1375

60-70

22

65

1430

70-80

16

75

1200

80-90

11

85

935

90-100

6

95

570

 

n = 100

 

∑f Xm = 6198

 

X  = ∑f Xm/n = 6330/100 = 63.30

Mean = 63.30

Example 4 – Calculate the mean number of hours per week spent by each student in texting message.

Time per week

0 - 5

5 - 10

10 - 15

15 - 20 

 20 - 25

 25 – 30

No. Of students

 8

11 

15

12 

9

5

 

Solution:

Time per week (X)

No. Of students (F)

Mid point X

XF

0 - 5

8

2.5

20

5 – 10

11

7.5

82.5

10 - 15

15

12.5

187.5

15 - 20

12

17.5

210

20 - 25

9

22.5

202.5

25 – 30

5

27.5

137.5

 

60

 

840

 

Mean = 840/60 = 14

 

Example 5 –

The following table of grouped data represents the weights (in pounds) of all 100 babies born at a local hospital last year.

Weight (pounds)

Number of Babies

[35)

8

[57)

25

[79)

45

[911)

18

[1113)

4

 

Solution:

Weight (pounds)

Number of Babies

Mid point X

XF

[35)

8

4

32

[57)

25

6

150

[79)

45

8

360

[911)

18

10

180

[1113)

4

12

48

 

100

 

770

 

Mean = 770/100 = 7.7

Geometric mean

Geometric mean is a type of mean or average, which indicates the central tendency of a set of numbers by using the product of their values.

Definition

The Geometric Mean (G.M) of a series containing n observations is the nth root of the product of the values.

For ungrouped data

Geometric Mean, GM = Antilog ∑logxi

N

Example 1 – find the G.M of the values

X

Log X

45

1.653

60

1.778

48

1.681

65

1.813

Total

6.925

 

GM = Antilog ∑logxi

N

= Antilog 6.925/4 

= Antilog 1.73

= 53.82

 

For grouped data

Geometric Mean, GM = Antilog ∑ f logxi

N

Example 2 – calculate the geometric mean

X

f

60 – 80

22

80 – 100

38

100 – 120

45

120 – 140

35

 

 

 

Solution

X

f

Mid X

Log X

f log X

60 – 80

22

70

1.845

40.59

80 – 100

38

90

1.954

74.25

100 – 120

45

110

2.041

91.85

120 – 140

35

130

2.114

73.99

Total

140

 

 

280.68

 

GM = Antilog ∑ f logxi

N

= antilog 280.68/140

= antilog 2.00

GM = 100

Example 3 – calculate geometric mean

Class

Frequency

2-4

3

4-6

4

6-8

2

8-10

1

 

Solution

Class

Frequency

x

Log x

Flogx

2-4

3

3

1.0986

3.2958

4-6

4

5

1.2875

6.4378

6-8

2

7

0.5559

3.8918

8-10

1

9

0.2441

2.1972

 

10

 

 

15.8226

 

GM = Antilog ∑ f logxi

N

= antilog 15.8226/10

= antilog 1.5823

GM = 4.866

 

Harmonic mean

Harmonic mean is quotient of “number of the given values” and “sum of the reciprocals of the given values

 

For ungrouped data

Example 1 - Calculate the harmonic mean of the numbers 13.2, 14.2, 14.8, 15.2 and 16.1

Solution

X

1/X

13.2

0.0758

14.2

0.0704

14.8

0.0676

15.2

0.0658

16.1

0.0621

Total

0.3147

 

H.M of X = 5/0.3147 = 15.88

Example 2 - Find the harmonic mean of the following data {8, 9, 6, 11, 10, 5} ?

X

1/X

8

0.125

9

0.111

6

0.167

11

0.091

10

0.100

5

0.200

Total

0.794

 

H.M of X = 6/0.794 = 7.560

 

For grouped data

Example 3 - Calculate the harmonic mean for the below data

Marks

30-39

40-49

50-59

60-69

70-79

80-89

90-99

F

2

3

11

20

32

25

7

 

Solution

Marks

X

F

F/X

30-39

34.5

2

0.0580

40-49

44.5

3

0.0674

50-59

54.4

11

0.2018

60-69

64.5

20

0.3101

70-79

74.5

32

0.4295

80-89

84.5

25

0.2959

90-99

94.5

7

0.0741

Total

 

100

1.4368

 

HM = 100/1.4368 = 69.59

Example 4 – find the harmonic mean of the given class

Ages

4

5

6

7

No. Of students

6

4

10

9

 

Solution

X

F

f/x

4

6

1.50

5

4

0.80

6

10

1.67

7

9

1.29

 

29.00

5.25

 

HM = 29/5.25 = 5.5

Example 5 – calculate harmonic mean

Class

Frequency

2-4

3

4-6

4

6-8

2

8-10

1

 

Solution

Class

Frequency

x

f/x

2-4

3

3

1

4-6

4

5

0.8

6-8

2

7

0.28

8-10

1

9

0.11

 

10

 

2.19

 

Harmonic mean = 10/2.19 = 4.55

 

Merits of mean

  1. It is rigidly defined
  2. It is easy to understand and easy to calculate
  3. It is based upon all values of the given data
  4. It is capable of future mathematical treatment
  5. It is not much affected by sampling fluctuation

Demerits of mean

  1. It cannot be calculated if any observation are missing
  2. It cannot be calculated for open end classes
  3. It is effected by extreme values
  4. It cannot be located graphically
  5. It may be number which is not present in the data

 


 

Terms and formulae, problem involving cost price, selling price, trade discount, cash discount

Cost Price (CP) - The price at which an article is purchased.

Selling Price (SP) - This is the price at which an article is sold.

Profit - If the selling price is more than the cost price, then there will be profit

Profit = Selling price (SP) – Cost price (CP)

 

Profit % = (profit100)/CP

 

Loss - If the selling price is less than the cost price, then there will be loss

Loss = Cost price (CP) – Selling price (SP)

Loss% = (Loss 100)/CP

 

Marked Price - This is the price marked as the selling price on an article, also known as the listed price

Note- Profit or Loss is always calculated on the cost price.

Discount: This is the reduction in price offered on the marked or listed price.

 

Example: Suppose the profit percentage is 80% of the cost. If the cost further increases by 20% but the selling price remains the same, how much is the decrease in profit percentage?

Sol.

Let us suppose

CP = Rs. 100.

Then Profit = Rs. 80 and selling price = Rs. 180.

The cost increases by 20% New CP = Rs. 120, SP = Rs. 180.

Profit % = 60/120 100 = 50%.

Therefore, Profit decreases by 30%.

 

Example: A dishonest shopkeeper sells his grocery using weights 15% less than the true weights and makes a profit of 20%. Find his total gain percentage.

Sol.

Suppose 1 kg of grocery bag.

Its actual weight is 85% of 1000 gm = 850 gm.

Let the cost price of each gram be Re. 1. Then the CP of each bag = Rs. 850.

SP of 1 kg of bag = 120% of the true CP

Therefore, SP = 120/100 1000 = Rs. 1200

Gain = 1200 – 850 = 350

Hence Gain % = 350/850 100 = 41.17%

Example: A shopkeeper offers a discount of 20% on the selling price. On a special sale day, he offers an extra 25% off coupon after the first discount. If the article was sold for Rs. 3600, find the marked price of the article

Sol.

Let the marked price of the article be x.

First a 20% discount was offered, on which another 25% discount was offered.

So, 75% of 80% of x = 3600

75/100 80/100 x = 3600 x = 6000.

So the article was marked at Rs. 6000.

 

Example: The cost price of 30 articles is equal to the selling price of 40 articles. What is the profit or loss percentage?

Sol.

CP of 30 articles = SP of 40 articles Or, CP/SP = 30/40 =3/4


Or, 1 – CP/SP = 1- 3/4 = 1/4

So, Loss percentage


= (l – CP/SP) x 100 = 1/4x 100 = 25%

 

Trade discount-

Trade discount is a certain percentage a manufacturer is willing to reduce its list price for wholesalers or retailers.

Trade discounts are given to wholesalers that order large quantities of a product as well as retailers with good relationships with the manufacturer. Purchase discounts or Cash discount are based on payment plans not order quantities.

Trade discounts are offered on bulk purchases by traders, wholesalers, distributors or retailers and not to the end consumers.

Trade discounts are generally offered at varied rates depending on the volume of sale

And

 

Example: Sweety purchases a set of toys that lists for Rs. 950 and it has a trade discount of 30%, then find the net price.

Sol.

As we know that-

 

Then

Net price = 950 – 285 = 665

 

Example: If Raheem will buy a table that lists for Rs. 2000 and it has a trade discount of 50%. Then how much will he pay?

Sol.

As we know that-

 

Then

Net price = 2000 – 1000 = 1000

 

Cash discountis allowed to stimulate instant payment of the goods purchased. 

Cash Discount is referred to as a discount, allowed to customers by the seller at the time of making the payment of purchases, as a reduction in the invoice price of the commodity.

Both the buyers and sellers keep a proper record of such discount in their books of accounts.

Sellers offer cash discounts to their buyers as an incentive to encourage early payment.

 

 

Ordinary dating method-

A credit term of [2/10, n/30] means that you will get a discount of 2% if you clear your account within 10 days

Example: A person received an invoice for Rs. 3,000 dated 22 November 2019 with terms [2/10, n/30]. He paid the whole amount on 30 November 2019. How much did he effectively paid for the bill?

Sol.

  1. Date of Invoice: 22nd November 2019
  2. Day 1 of the cash discount period.  : 23rd November 2019
  3. Last day of the Cash discount period: 31st November 2019
  4. Date of payment: 30th November 2019

Cash discount.= Price Discount rate

= Rs. 3,000 2/100

= Rs. 60

Amount effectively paid by the person = Bill value - Cash discount

= 3,000 - 60

= Rs. 2,940

 

Key takeaways-

  1. Cost Price (CP) - The price at which an article is purchased
  2. Selling Price (SP) - This is the price at which an article is sold
  3. Profit = Selling price (SP) – Cost price (CP)
  4. Profit = Selling price (SP) – Cost price (CP)
  5. Loss = Cost price (CP) – Selling price (SP)
  6. Loss% = (Loss 100)/CP
  7. Marked Price - This is the price marked as the selling price on an article, also known as the listed price
  8. Discount: This is the reduction in price offered on the marked or listed price.
  9. Trade discount is a certain percentage a manufacturer is willing to reduce its list price for wholesalers or retailers.
  10. Trade discounts are generally offered at varied rates depending on the volume of sale

Introduction to commission and brokerage- problems on commission and brokerage

 

The amount received by the agency for providing its services is known as ‘brokerage’ or ‘commission’.

For example- placement agencies, marriage bureaus etc.

An individual can also run this type of business

Note- An individual who acts as a ‘middle man’ between a seller and buyer is known as broker.

Brokerage is paid by purchaser, Commission is paid by seller. Therefore

 

Net amount paid by purchaser = Sale price + brokerage

Net amount received by seller = Sale price - commission

 

Commission % = Commission100 /Selling price

Selling Price = Commission100/ Commission %

Commission (Brokerage) = Commission%Selling price/100

 

Example: The Price of a book is Rs. 15.75. A book seller sells 1200 books and pays Rs 17,860.50 to the book publisher after deducting his commission.  

Find the commission rate.

Sol.

Here we have total commission,

We have to find the total sale price of books.

 

The total sale price of books = Number of Books Price = 120015.75 =18900

Commission = Sale price – Amount paid to the Publisher = 18900-17860.5 = 1039.5

Commission % = Commission100 /Selling price = 1039.5100/18900 = 5.5%

 

Example: Mahesh sold his car for Rs.68,000 with the help of an agent. If the commission paid by Mahesh is Rs 2550. Find rate of commission, and the net amount received  by the Mahesh.

Sol.

Commission % = Commission100 /Selling price = 2550100/68000 = 3.75%

Net amount received by farmer = Sale price – Commission = 68000-2550 = Rs65, 450

 

Example: An agency pays 15% commission to a notebook distributor. The price of each notebook is Rs 3. If he sells 50 copies of notebook every day, find how much commission he receives in a month and also net amount received by the Agency?

Sol.

Price of each news paper = Rs 3.

Sale price for a day = Number copies sold in day price of Cost of news paper = 503 = Rs 150

Sale price for a year = Number of daysSale price for a day = 30150 = 450 Rs

Commission = Commission%Selling price/100 = 15450/100 = 67.5 Rs.

Net amount received by agency = selling price – commission = 450 -67.5 = 382.5 Rs

 

Key takeaways-

  1. Net amount paid by purchaser = Sale price + brokerage

Net amount received by seller = Sale price - commission

2.     Commission % = Commission100 /Selling price

3.     Selling Price = Commission100/ Commission %

4.     Commission (Brokerage) = Commission%Selling price/100

 


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