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5.1 Classical Plate theory (KCPT)

Assumptions-

● Thickness is smaller than the other dimension.

● Displacements are much smaller than plate thickness.

● Governing equations are based on undeformed geometry.

● Materials follow Hook’s Law.

● The middle surface is always unstrained during bending.

● The Plane normal to the middle surface remains normal.

● Rotatory inertia is negligible. Transverse shear strains also negligible.

Let us consider a thin plate in xy plane as given in the figure-

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Figure 5.1 A thin plate

Moments-

Moment wrt to y-axis- let us consider a cubical small element as shown in figure we will get

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Figure 5.2 Small differential element

dFxx =σxx dz

Moment wrt to x-axis- (similarly)-

Twisting moment of shear stress

Using the section module formula of the beam –

Shear forces

Vertical equilibrium of plate-

Substituting the above equation we get-

Shear force according to thickness-

Governing Equation

For Qx –

w) =

Bi-harmonic governing equation

5.2 Boundary Conditions

There are three possibilities of boundary condition-

Simply supported-

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Figure 5.3- Middle plane

For x constant –

w( x , y ) = 0

For edge y constant-

W=0

2. Clamped-

For x constant –

W=0

For y constant-

W=0

3. Free edge-

For x constant-

Bending moment-

Moment xy and shear –

For y constant-

Bending moment-

=0

Shear force-

5.3 Navier’s method for a simply supported rectangular plate

Navier solution for lateral deflection of a simply supported rectangular plate having dimension a and b with distributed q as shown in the figure-

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Figure 5.4- Simply supported plate

Where m, n=1,3,5……

Multiply both side by sin(jπx/a) sin(kπy/b) and integrate wrt x and y from 0 to a

and 0 to b-

……(1)

Integrating wrt x-

Integrating wrt y-

At m = j

=

Similarly at n=k –

Now the equation(1) will be –

Substituting w and q(x,y) in the fourth-order governing differential equation-

Now the W-

Integrating equation (2) wrt x and y-

And

Substituting the above two values in the equation number (2) we will get-

Now the equation (1) will be –

This is the equation of deflection for UDL using the Navier method for method.

5.4 Levy’s Method of Solution for Rectangular Plates

Let us consider a thin plate in xy plane in which at y=0 and y=b are simply supported and at x=0 and x=a can have any support like(clapped, free or simply supported) as shown in the figure –

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Figure 5.5- Neutral plane of thin plate

A suitable governing equation for this case will be-

For an isotropic plate-

Let us consider this is a square plate a=b=1m, n=1 made of steel and n=1 then-

Because it is a differential equation of fourth-order. Hence it will give two solution-

Where λ is the roots of the equation.

If

For isotropic plate r12 = π2, now the roots will be-

and

The solution-

And

The final solution will be-

The above equation is the solution for the plate using the Levy theorem.

Key Takeaway:

KCPT

2.

3.

4.

5.

6. Navier Method For plate (deflection)

7. Levy theorem For plate

REFERENCES-

Book- Mechanics by Fridtjov Irignes Chapter-7
Sadd 9.3, Timoshenko Chapter-11
Module 9 version 2 ME, IIT Kharagpur
Book- solid mechanics- 2nd by Kelly

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