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Unit-6

Multiple Access Techniques

 

Q1) Explain time division multiplexing?

A1) In TDM the complete channel bandwidth is allotted to one user for fixed time slot. For instance, if there are ten users then every user can be given the time slot of one second. Thus, complete channel can be used by each user for one second time in every ten seconds.

 

 

Fig 1 Time Division Multiplexing

This technique is suitable for digital signals because the digital signals are transmitted intermittently and the time spacing between two successive digital codewords can be utilised by other signals

 

Q2) Explain types of TDM?

A2) The TDM is classified in two types

Synchronous TDM

In synchronous time division multiplexing, each transmitter is allotted with a fixed time slot, regardless of the fact that the transmitter has any data to transmit or not. The device has to transmit data within this time slot. If the transmitter does not have any data to send then its time slot remains empty.

Fig 2 Synchronous TDM

 

The above figure shows four dedicated time slots A, B, C and D. The transmitter A data is sent at time slot A, transmitter B data is sent at time slot B, transmitter C data is sent at time slot C and transmitter D data is sent at time slot D.

In the time frame 2, the transmitter B and C does not have any data to send so the time slot B and C remains empty. 

The main drawback of synchronous time division multiplexing is that the channel capacity is not fully utilized. Hence, the bandwidth goes wasted.

 

Asynchronous TDM

In this case the time slots are not fixed. The number of transmitters are not equal to the number of time slots. In asynchronous TDM the number of slots are always less than the transmitters.

Fig 3 Asynchronous TDM

 

As seen from above figure the system has four transmitters and 3 time slots. Frame 1 is completely filled with data from devices A, B, C and D. Frame 1 has only 3 time slots. The data from D is filled in frame 2 in timeslot 1. The data from A and D are filled in timeslot 2 and 3 in time frame 2.

In asynchronous time division multiplexing, the multiplexer scans all the transmitters and accepts input only from the devices that have actual data to send and fills all the frames, and then sends it to the receiver. If there is not enough data to fill all the slots in a frame, then the partially filled frames are transmitted. In most of the cases, all the time slots in frames are completely filled.

 

Q3) Explain frequency division multiplexing?

A3) This technique allows to allot a fixed frequency band to every user in the complete channel bandwidth. Such frequency slot is allotted to each frequency user. The figure shows FDM below. The transmitter end contains multiple receivers and transmitters. The transmitter end sends a signal of different frequency. The transmtter1 sends signal of 30kHz, transmitter 2 sends signal of 40kHz and so on as shown below. These signals of different frequencies are multiplexed and transmitted.

Fig 4 Frequency Division Multiplexing

 

At the receiver end, the multiplexed signals are separated by using a device called demultiplexer. It then sends the separated signals to the respective receivers. In the above figure, the receiver 1 receives signal of 30 kHz, receiver 2 receives signal of 40 kHz, and receiver 3 receives signal of 50 kHz.

 

Q4) List the differences between TDM and FDM?

A4)

 

Q5) Explain the application of CDM?

A5)

  • CDMA stands for Code Division Multiple Access. CDMA is a technique for spread spectrum multiple access.
  • Data signals are XOReD with pseudorandom code and then transmitted over a channel.
  • Different codes are used to modulate their signals, selection of code to modulate is important aspect as it relates with performance of system.
  • In CDMA, single channel uses entire bandwidth and it does not share time as all stations transmit data simultaneously. Due to this CDMA differ from FDMA and TDMA.
  • Let us assume we have 4 different stations A, B, C and D. All 4 stations connected to same channel. Data from station A is d1, B is d2, C is d3 and D is d4 similarly code assigned to A is C1, B is C2, C is C3 and D is C4.
  • To transmit data, all 4 stations have multiplication strategy i.e. either code multiply by itself. It results in 4 stations or code multiply results in 4 stations or code multiply results in 4 station of code multiply by another, it results in zero station.
  •  

     

    Fig.5: Communication of station with code

  • If station C and station D are talking to each other, D wants to listen whatever C is saying. It multiplies data on channel by C3 of station C.
  • As C3 C3 is 4 and rest of combination i.e. C1 C3, C2 C3  and C4 C3 are all zero.
  • Every station has some code, which is sequence of numbers known as chips.
  • Sequence should be selected in proper manner to get appropriate codes. Orthogonal sequence has some properties :
  • Multiplication of sequence by a scalar.
  • Inner product of two equal sequences.
  • Inner product of two different sequences.
  • Sequence generation uses Walsh table to generate chip sequence.
  •  

    Q6) Explain the FDMA and TDMA techniques?

    A6)

    FDMA

  • It sub-divide frequency into a several frequency band with non-overlapping.
  • Fig.6 FDMA

  • FDMA allows user to transmit signals simultaneously to satellite transponder with the help of assigning a specific frequency to every user among a channel.
  • Each transaction of signal has own unique radio channel. Channel are probably 30 KHz or less used to transmit or receive channels.
  • Frequency allocation made by national policies. Uplink (i.e. from mobile station to base station). Downlink (i.e. from base station to mobile station) uses frequencies bands like. Uplink and downlink with frequencies mentioned below :
  • Uplink

    890.2 MHz, 915 MHz

    Downlink

    935.2 MHz to 960 MHz

    Uplink (UL) and downlink (DL) can be described with the help of one relation among them as follows:

    fd = fu + 45 MHz

  • For Example :
  • If UL frequency is :

    fu = 890 MHz + n∙ 0. 2 MHz

    Then

    fd = 935 MHz + n ∙ 0. 2 MHz

  • Fixed assigned frequency makes scheme very inflexible limits to no. of sender turn into disadvantage of FDMA.
  •  

    TDMA

     

  • It is based on time slots. TDMA more flexible than FDMA scheme.
  • Dynamic allocation of channel or by some fixed pattern channels get allotted for time slots to takes places synchronized communication.
  •  

    Fig. 7 TDMA

  • Fixed channel are allocated for communication as best practice solution for wireless phone system in Medium Access Control (MAC) reserved time slot access is for crucial.
  •  

    Q7) Explain the frequency reuse in mobile communication?

    A7)

  • It is process of combining analog and digital signal to send over shared medium.
  • It divides the capacity of communication channel into multiple channels
  • Multiplexing is divided into space division, frequency division and time division multiplexing.
  • Space Division Multiplexing

  • In wired medium, separate point to point conductors are used to each channel.
  • In wireless medium multiple elements of antennas are used such that it forms phased array antenna.
  • Multiple output, multiple input and single input multiple output are the examples of this.
  •          Frequency Division Multiplexing

  • In these multiple signals are send in distinct frequency in single medium.
  • The signals are electrical.
  • Radio, television broadcasting are the examples of FDM.
  • The service provides can send several channels or signals continuously to all subscribers even the customer has single cable connection.
  •  

    Time Division Multiplexing

  • In this for separation of data streams the time is used instead of frequency and space.
  • It consists of group of bits in sequence one after another.
  • Each sequence is associated with each receiver.
  • Carriers sense multiple access and multidrug are the eaxples of time division multiplexing.
  •  

    Q8) Explain the difference between possible multiple access techniques?

    A8)

    Approach

    SDMA

    TDMA

    FDMA

    CDMA

    Idea

    Segment space into cells/sectors

    Segment sending time into disjoint time-slots, demand driven or fixed patters

    Segment the frequency band into disjoint sub-bands

    Spread the spectrum using orthogonal codes

     

    Terminals

    Only one terminal can be active in one cell/one sector

    All terminals are active for short periods of time on the same frequency

    Every terminal has its own frequency. uninterrupted

    All terminals can be active at the same place at the same moment uninterrupted.

    Signal separation

    Cell structure, directed antennas

    Synchronization in the time  domain

    Filtering in the frequency domain

    Code plus special receivers

    Advantages

    Very simple, increases capacity per km2

    Established, fully digital, flexible

    Simple, established robust

    Flexible, less frequency planning needed, soft handover 

    Disadvantages

     Inflexible, antennas typically fixed

    Guard space needed (multipath propagation), synchronization difficult

    Inflexible, frequencies are a scarce resource

    Complex receivers, needs more complicated power control for senders

    Comment

    Only in combination with TDMA, FDMA or CDMA useful

    Standard in fixed networks, together with FDMA/SDMA used in many mobile networks

    Typically combined with TDMA (frequency hopping patterns) and SDMA (frequency reuse)

    Still faces some problems, higher complexity, lowered expectations : will be integrated with TDMA/FDMA

     

    Q9) What are SONET. Explain in detail it’s all layers?

    A9) It defines the rate and format for the optical transmission of digital data. The data rates of 51.84Mb/s to 9.953Gb/s are specified by SONET. This system has four layers.

  • Photonic Layer: This specifies the type of optical fiber, the minimum required laser powers, sensitivity of the receiver and dispersion characteristics of lasers.
  • Section Layer: This layer generates SONET frames and converts the electronic signal to photonic signals.
  • Line Layer: It synchronizes and multiplexes the data into SONET frames.
  • Path Layer: It performs end to end transport of data at the power rate.
  •  

    Q10) What are problem in multipath propagation?

  • A10) Multi path causes large and rapid fluctuations in a signal
  • These fluctuations are not the same as the propagation path loss.
  • Multipath causes three major things in wireless communication

  • Rapid changes in signal strength over a short distance or time.
  • Random frequency modulation due to Doppler Shifts on different multipath signals.
  • Time dispersion caused by multipath delays
  • These are called “fading effects
  • Multipath propagation results in small-scale fading.
  •