Unit 4
Unit 4
Algebraic structure and morphism
Q1) Consider an algebraic system (N, +), where the set N = {0, 1, 2, 3, 4...}.The set of natural numbers and + is an addition operation. Determine whether (N, +) is a monoid.
Solution: (a) Closure Property: The operation + is closed since the sum of two natural numbers.
(b)Associative Property: The operation + is an associative property since we have (a+b)+c=a+(b+c) ∀ a, b, c ∈ N.
(c)Identity: There exists an identity element in set N the operation +. The element 0 is an identity element, i.e., the operation +. Since the operation + is a closed, associative and there exists an identity. Hence, the algebraic system (N, +) is a monoid.
Q2) Let G be a permutation group on an infinite set X. There is a graded algebra A[G] associated with G as follows: the nth homogeneous component Vn is the set of all G-invariant functions from the set of n-element subsets of X to the complex numbers; multiplication is defined by the rule that, if f in Vn, g in Vm, and K is an (n+m)-element set then
(fg)(K) = sum f(L)g(K-L) : L subseteq K, |L| = n.
Solution :
The constant function e in V1 with value 1 is not a zero-divisor. We say that G is entire if A[G] is an integral domain, and strongly entire if A[G]/eA[G] is an integral domain. It is conjectured that G is (strongly) entire if and only if it has no finite orbits on X. In the absence of a proof of this conjecture, can one show the following:
If the permutation groups G1 on X1 and G2 on X2 are (strongly) entire, then G1 × G2 (in its intransitive action on X1 union X2) is (strongly) entire.
Q3) Find the truth value and from that information find the logically equivalent disjunctive normal form.
a. [(p q) r] b. P (q r)
Solution: a. (p q r) V (p q r) V (p q r)
b. (p q r) V (p q r) V (p q r) (circled false outputs)
Q4) Consider an algebraic system (G, *), where G is the set of all non-zero real numbers and * is a binary operation defined by
Show that (G, *) is an abelian group.
Solution:
Closure Property: The set G is closed under the operation *, since a * b = is a real number. Hence, it belongs to G.
Associative Property: The operation * is associative. Let a,b,c∈G, then we have
Identity: To find the identity element, let us assume that e is a +ve real number. Then e * a = a, where a ∈G.
Thus, the identity element in G is 4.
Q5) Consider the lattice of all +ve integers I+ under the operation of divisibility. The lattice Dn of all divisors of n > 1 is a sub-lattice of I+.
Determine all the sub-lattices of D30 that contain at least four elements, D30={1,2,3,5,6,10,15,30}.
Solution: The sub-lattices of D30 that contain at least four elements are as follows:
1. {1, 2, 6, 30} 2. {1, 2, 3, 30}
3. {1, 5, 15, 30} 4. {1, 3, 6, 30}
5. {1, 5, 10, 30} 6. {1, 3, 15, 30}
7. {2, 6, 10, 30}
Q6) Write the dual of following Boolean expressions:
1. (x1*x2) + (x1*x3') 2. (1+x2)*( x1+1)
3. (a ∧(b∧c))
Solution:
1. ( x1+x2)*( x1+x3') 2. (0*x2)+( x1*0)
3. (a ∨(b∧c))
Q7) Simplify: AB(A + B)(B + B):
Expression | Rule(s) Used | ||||||||||||||||||||||||||
AB(A + B)(B + B) | Original Expression | ||||||||||||||||||||||||||
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AB(A + B) | Complement law, Identity law. | ||||||||||||||||||||||||||
(A + B)(A + B) | DeMorgan's Law | ||||||||||||||||||||||||||
A + BB | Distributive law. This step uses the fact that or distributes over and. It can look a bit strange since addition does not distribute over multiplication. | ||||||||||||||||||||||||||
A | Complement, Identity. | ||||||||||||||||||||||||||
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Q8) Simplify: A(A + B) + (B + AA)(A + B):
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Q9)) Show that (2, 5) encoding function e B2 B5 defined by
e(00) = 01100e(10) = 10001
e (01) = 01110e(11) = 11011
Is a group code.
Unit 4
Unit 4
Algebraic structure and morphism
Q1) Consider an algebraic system (N, +), where the set N = {0, 1, 2, 3, 4...}.The set of natural numbers and + is an addition operation. Determine whether (N, +) is a monoid.
Solution: (a) Closure Property: The operation + is closed since the sum of two natural numbers.
(b)Associative Property: The operation + is an associative property since we have (a+b)+c=a+(b+c) ∀ a, b, c ∈ N.
(c)Identity: There exists an identity element in set N the operation +. The element 0 is an identity element, i.e., the operation +. Since the operation + is a closed, associative and there exists an identity. Hence, the algebraic system (N, +) is a monoid.
Q2) Let G be a permutation group on an infinite set X. There is a graded algebra A[G] associated with G as follows: the nth homogeneous component Vn is the set of all G-invariant functions from the set of n-element subsets of X to the complex numbers; multiplication is defined by the rule that, if f in Vn, g in Vm, and K is an (n+m)-element set then
(fg)(K) = sum f(L)g(K-L) : L subseteq K, |L| = n.
Solution :
The constant function e in V1 with value 1 is not a zero-divisor. We say that G is entire if A[G] is an integral domain, and strongly entire if A[G]/eA[G] is an integral domain. It is conjectured that G is (strongly) entire if and only if it has no finite orbits on X. In the absence of a proof of this conjecture, can one show the following:
If the permutation groups G1 on X1 and G2 on X2 are (strongly) entire, then G1 × G2 (in its intransitive action on X1 union X2) is (strongly) entire.
Q3) Find the truth value and from that information find the logically equivalent disjunctive normal form.
a. [(p q) r] b. P (q r)
Solution: a. (p q r) V (p q r) V (p q r)
b. (p q r) V (p q r) V (p q r) (circled false outputs)
Q4) Consider an algebraic system (G, *), where G is the set of all non-zero real numbers and * is a binary operation defined by
Show that (G, *) is an abelian group.
Solution:
Closure Property: The set G is closed under the operation *, since a * b = is a real number. Hence, it belongs to G.
Associative Property: The operation * is associative. Let a,b,c∈G, then we have
Identity: To find the identity element, let us assume that e is a +ve real number. Then e * a = a, where a ∈G.
Thus, the identity element in G is 4.
Q5) Consider the lattice of all +ve integers I+ under the operation of divisibility. The lattice Dn of all divisors of n > 1 is a sub-lattice of I+.
Determine all the sub-lattices of D30 that contain at least four elements, D30={1,2,3,5,6,10,15,30}.
Solution: The sub-lattices of D30 that contain at least four elements are as follows:
1. {1, 2, 6, 30} 2. {1, 2, 3, 30}
3. {1, 5, 15, 30} 4. {1, 3, 6, 30}
5. {1, 5, 10, 30} 6. {1, 3, 15, 30}
7. {2, 6, 10, 30}
Q6) Write the dual of following Boolean expressions:
1. (x1*x2) + (x1*x3') 2. (1+x2)*( x1+1)
3. (a ∧(b∧c))
Solution:
1. ( x1+x2)*( x1+x3') 2. (0*x2)+( x1*0)
3. (a ∨(b∧c))
Q7) Simplify: AB(A + B)(B + B):
Expression | Rule(s) Used | ||||||||||||||||||||||||||
AB(A + B)(B + B) | Original Expression | ||||||||||||||||||||||||||
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AB(A + B) | Complement law, Identity law. | ||||||||||||||||||||||||||
(A + B)(A + B) | DeMorgan's Law | ||||||||||||||||||||||||||
A + BB | Distributive law. This step uses the fact that or distributes over and. It can look a bit strange since addition does not distribute over multiplication. | ||||||||||||||||||||||||||
A | Complement, Identity. | ||||||||||||||||||||||||||
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Q8) Simplify: A(A + B) + (B + AA)(A + B):
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Q9)) Show that (2, 5) encoding function e B2 B5 defined by
e(00) = 01100e(10) = 10001
e (01) = 01110e(11) = 11011
Is a group code.