Module-2
Eigen values and eigen vectors
Q1: Find the sum and the product of the Eigen values of ?
A1:
The sum of Eigen values = the sum of the diagonal elements
=1+(-1)=0
The product of the Eigen values is the determinant of the matrix
On solving above equations we get
Q2: Find out the Eigen values and Eigen vectors of
A2:
Let A =
The characteristics equation of A is .
Or
Or
Or
Or
The Eigen vector corresponding to Eigen value is
Where X is the column matrix of order 3 i.e.
Or
On solving we get
Thus the Eigen vectors corresponding to the Eigen value is (1,1,1).
The Eigen vector corresponding to Eigen value is
Where X is the column matrix of order 3 i.e.
Or
On solving or .
Thus the Eigen vectors corresponding to the Eigen value is (0,0,2).
The Eigen vector corresponding to Eigen value is
Where X is the column matrix of order 3 i.e.
Or
On solving we get or .
Thus the Eigen vectors corresponding to the Eigen value is (2,2,2).
Hence three Eigen vectors are (1,1,1), (0,0,2) and (2,2,2).
Q3: Find the Eigen values of Eigen vector for the matrix.
A3:
Consider the characteristic equation as
i.e.
i.e.
are the required eigen values.
Now consider the equation
… (1)
Case I:
Equation (1) becomes,
Thus and n = 3
3 – 2 = 1 independent variables.
Now rewrite the equations as,
Put
,
I.e.
the Eigen vector for
Case II:
If equation (1) becomes,
Thus
Independent variables.
Now rewrite the equations as,
Put
Is the Eigen vector for
Now
Case III:-
If equation (1) gives,
R1 – R2
Thus
Independent variables
Now
Put
Thus
Is the Eigen vector for
Q4: Show that any square matrix can be expressed as the sum of symmetric matrix and anti- symmetric matrix.
A4:
Suppose A is any square matrix .
Then,
A =
Now,
(A + A’)’ = A’ + A
A+A’ is a symmetric matrix.
Also,
(A - A’)’ = A’ – A
Here A’ – A is an anti – symmetric matrix
So that,
Square matrix = symmetric matrix + anti-symmetric matrix
Q5: prove Q= is an orthogonal matrix
A5:
Given Q =
So, QT = …..(1)
Now, we have to prove QT = Q-1
Now we find Q-1
Q-1 = … (2)
Now, compare (1) and (2) we get QT = Q-1
Therefore, Q is an orthogonal matrix.
Q6: Express the matrix A as sum of hermitian and skew-hermitian matrix where
A6:
Let A =
Therefore and
Let
Again
Hence P is a hermitian matrix.
Let
Again
Hence Q is a skew- hermitian matrix.
We Check
P +Q=
Hence proved.
Q7: Diagonalise the matrix
A7:
Let A=
The three Eigen vectors obtained are (-1,1,0), (-1,0,1) and (3,3,3) corresponding to Eigen values .
Then and
Also we know that
Q8: Diagonalise the matrix
A8:
Let A =
The Eigen vectors are (4,1),(1,-1) corresponding to Eigen values .
Then and also
Also we know that
Q9: Write down the properties of Eigen vector.
A9:
Properties of Eigen vector:-
Q10: Write down the properties of Eigen values.
A10:
Properties of Eigen values:-