UNIT 1

Quantum Chemistry and Spectroscopy

Q1) Discuss about classical plane wave equation.

A1) A wave is a disturbance of a physical quantity undergoing simple harmonic motion or oscillations about its place. The disturbance gets passed on to its neighbors in a sinusoidal form.

The equation for the wave is a second-order partial differential equation of a scalar variable in terms of one or more space variable and time variable. The one-dimensional wave equation is-

The amplitude (y) for example of a plane progressive sinusoidal wave is given by:

where, A is the maximum amplitude, T is the period and φ is the phase difference of the wave if any and t is the time in seconds. For a standing wave-

Q2) What are Lambert Beer’s Law?

A2) The amount of energy transmitted or absorbed by a solution is proportional to the solutions molar absorptive and the concentration of solute. In simple terms, a more concentrated solution absorbs more light than a more dilute solution does. Mathematically this can be expressed by

A=ε/C

where,

A = absorption,

Ε = molar attenuation coefficient

I = path length

C = concentration of the solution

Q3) Derive Beer-Lambert Law.

A3) The Beer-Lambert law can be derived from an approximation for the absorption coefficient for a molecule by approximating the molecule by an opaque disk whose cross-sectional area  represents the effective area seen by a photon of frequency w. If the frequency of the light is far from resonance, the area is approximately 0, and if w is close to resonance the area is a maximum. Taking an infinitesimal slab, dz, of sample:

Io is the intensity entering the sample at z=0, Iz is the intensity entering the infinitesimal slab at z, dI is the intensity absorbed in the slab, and I is the intensity of light leaving the sample. Then, the total opaque area on the slab due to the absorbers is   * N * A * dz. Then, the fraction of photons absorbed will be  * N * A * dz / A so,

dI / Iz = -  * N * dz

Integrating this equation from z = 0 to z = b gives:

In (I) – ln (Io) = -  * N * b

- ln (I / Io) =  * N * b.

Since N (molecules/cm3) * (1 mole / 6.023x1023 molecules) * 1000 cm3 / liter = c (moles/liter) and 2.303 * log(x) = ln(x) then

- log (I / Io) =  * (6.023x1020 / 2.303) * c * b

- log (I / Io) = A =  * b * c

Where, 

 =  * (6.023x1020 / 2.303) =  * 2.61x1020

Q4) Enlist the applications of UV Visible spectroscopy.

A4) Applications:

1-     This is majorly used in the analytical chemistry.

2-     This can be used as a detector for the High performance liquid chromatography.

3-     Ultraviolet-Visible Spectroscopy is used as the semiconductor in the industry to measure the thickness and optical properties of water.

Q5) What is monochromator?

A5) Monochromator used to measure the wavelength of the light. Monochromator is placed between the sample and the source of light passing from that the light passes to the detector. Here the monochromatic used to detect the wavelength of the light form the source. While on moving further there is a Double beam Ultraviolet-Visible instrument is used here is a splitter and a series of mirrors to get the beam to a reference sample and the sample to be analyzed, this allows for more accurate readings. In the simultaneous Ultraviolet-Visible instruments monochromator is removed hence it has diode array detectors that allow the instrument to simultaneously detect the absorbance at all wavelengths. This instrument is much faster and accurate than double and single Ultraviolet-Visible instrument.

Q6) What are chromophores?

A6)It is used in the denotation of some structural features of which gives color to compound. E.g. Nitro group is a chromophore because its presence in a compound gives yellow color to the compound. But these days the term chromophore is used in a much broader sense which may be defined as “any group which exhibit absorption of electromagnetic radiation in a visible or ultra-visible region “It may or may not impart any color to the compound. Some of the important chromophores are: ethylene, acetylene, carbonyls, acids, esters and nitrile groups etc. There are two types of chromophores:
1.  Chromophores in which the groups have π electrons undergo π-π* transitions. For examples:-ethylenes, acetylenes etc.
2.  Chromophores having both π- electrons and n (non-bonding) electrons undergo two types of transitions. i.e., π-π* and n-π*, for examples: - carbonyls, nitriles and nitro compounds etc.

Q7) Enlist the application of quantitative analysis.

A7) Applications on quantitative analysis:

1                    This is used in clinical and pre-clinical application in cancer.

2                    This is used in the investigation of platelets quality.

3                    Quantitative monitoring of an activated sludge reactor using on-line UC-Visible and near-infrared spectroscopy.

4                    The UV spectroscopy is used in the evaluation of pearl quality.

Q8) What are Rotational Spectroscopy?

A8) Rotational Spectroscopy is also called as the microwave spectroscopy. It is the measurement of energy of transition between quantized rotational states of molecules in the gas phase. The rotational spectra of non-polar molecules cannot be observed by this method while it can be measured by Raman spectroscopy. Rotational spectroscopy is sometimes referred to as pure rotational spectroscopy to distinguish it from rotational-vibrational spectroscopy where changes in rotational energy occur together with changes in vibrational energy and also from ro-vibronic spectroscopy (or just vibronic spectroscopy) where rotational, vibrational and electronic energy changes occur simultaneously. The molecules of the Rotational spectroscopy are classified according to their symmetry. The important feature of molecular rotational spectroscopy for chemical analysis is that the resolution of the spectral transitions is sufficiently high that the spectra of isomers with only small changes in mass distribution can be measured without spectral overlap. For example, the 13C- isotopologues of molecules, isomers created when a single carbon atom is isotopically substituted, are routinely resolved in the instruments used for rotational spectroscopy. The extreme sensitivity changes to in the mass distribution make rotational spectroscopy well-suited to distinguishing diaestromers of molecules with multiple chiral centers. A second advantage of the high-resolution of the spectrometers is that complex sample mixtures can be analyzed directly without spectral overlap. An example of the rotational spectrum from the vapor head space of an essential oil will be presented later to illustrate this capability.

Q9) Explain the principles of Rotational Spectroscopy.

A9) Rotational Spectroscopy is also called as the microwave spectroscopy. It is the measurement of energy of transition between quantized rotational states of molecules in the gas phase. The rotational spectra of non-polar molecules cannot be observed by this method while it can be measured by Raman spectroscopy. Rotational spectroscopy is sometimes referred to as pure rotational spectroscopy to distinguish it from rotational-vibrational spectroscopy where changes in rotational energy occur together with changes in vibrational energy and also from ro-vibronic spectroscopy (or just vibronic spectroscopy) where rotational, vibrational and electronic energy changes occur simultaneously. The molecules of the Rotational spectroscopy are classified according to their symmetry. The important feature of molecular rotational spectroscopy for chemical analysis is that the resolution of the spectral transitions is sufficiently high that the spectra of isomers with only small changes in mass distribution can be measured without spectral overlap. For example, the 13C- isotopologues of molecules, isomers created when a single carbon atom is isotopically substituted, are routinely resolved in the instruments used for rotational spectroscopy. The extreme sensitivity changes to in the mass distribution make rotational spectroscopy well-suited to distinguishing diaestromers of molecules with multiple chiral centers. A second advantage of the high-resolution of the spectrometers is that complex sample mixtures can be analyzed directly without spectral overlap. An example of the rotational spectrum from the vapor head space of an essential oil will be presented later to illustrate this capability.

Q10) Explain Infrared Spectroscopy and its applications.

A10) The change in the vibrational motion of molecule is absorbed in the Infrared Region this is why it is also called as the Infrared Spectroscopy. If vibration in the molecule persists then it should change its dipole moment that may be the magnitude form or oriented with its direction. When taking the example of Polar molecule (A-B) as the polar molecule shows the property of the high electronegative atom attracts the electron pair towards it so that it gets partial negative and partial positive charges. So in the polar molecule the atoms are making rotation therefore one side is positive pole while other is negative but due to the rotation at its own axis then there is no change in the magnitude effects hence it posses the generation of magnetic field which in result there in the electric flux or there is a change in the direction.

Taking the molecule A-B in consideration then the one get partial negative while other will be partial positive charge. There are two different type of vibration that is Coupled vibration and De-Coupled Vibrations.  The change in the relative position of 2 atoms is called as the coupled vibration while de-coupled vibration means  1 atom get fixed at a single position instead the other atom is in rotation. The vibration leads to the expansion and contraction of the atoms in the molecule. The change in the dipole movement due to the vibration then only those molecule exhibits vibrational spectroscopy.

Applications: