Unit-3
Vector differential calculus
Q1: A particle moves along the curve , here ‘t’ is the time. Find its velocity and acceleration at t = 2.
A1:
Here we have-
Then, velocity
Velocity at t = 2,
=
Acceleration =
Acceleration at t = 2,
Q2: If and then find-
1.
2.
A2:
We know that-
2.
Q3: A particle is moving along the curve x = 4 cos t, y = 4 sin t, z = 6t. then find the velocity and acceleration at time t = 0 and t = π/2.
And find the magnitudes of the velocity and acceleration at time t.
A3:
suppose
Now,
At t = 0 | 4 |
At t = π/2 | -4 |
At t = 0 | |v|= |
At t = π/2 | |v|= |
Again acceleration-
Now-
At t = 0 | |
At t = π/2 | |
At t = 0 | |a|= |
At t = π/2 | |a|= |
Q4: Define scalar point function and vector point function.
A4:
Scalar point function-
If for each point P of a region R, there corresponds a scalar denoted by f(P), in that case f is called scalar point function of the region R.
Note-
Scalar field- this is a region in space such that for every point P in this region, the scalar function ‘f’ associates a scalar f(P).
Vector point function-
If for each point P of a region R, then there corresponds a vector then is called a vector point function for the region R.
Q5: A object move in the path where t is the time in seconds and distance is measured in feets.
Then find and as functions of t.
A5:
We know that-
And
Now we will use-
And now-
Q6: If , then show that
A6:
Suppose and
Now taking L.H.S,
Which is
Hence proved.
Q7: If then find grad f at the point (1,-2,-1).
A7:
Now grad f at (1 , -2, -1) will be-
Q8: Show that-
1.
2.
A8:
We know that-
2. We know that-
= 0
Q9: If then find the divergence and curl of .
A9:
we know that-
Now-
Q10: If then prove that grad u , grad v and grad w are coplanar.
A10:
Here-
Now-
Apply
Which becomes zero.
So that we can say that grad u, grad v and grad w are coplanar vectors.