UNIT-1
UNIT-1
Q 1: Solve the following improper Integral
Solution:
Given,
Q2: Solve the following improper Integral
Solution: Given,
Q3: Solve the following improper Integral
Solution: Given,
Q 4 : Solve the following improper Integral
Solution: Given,
Q 5: evaluate the integral
Solution: we use
Substituting a=2x
Hence,
=
=
=
=
Q 6: Evaluate the integral
Solution: we use the formula
=
= .
Q 7: f(B) = Solve the given function.
Solution: =
= [Recursive function for the gamma function]
= [Recursive formula for the gamma function]
=
= [By the definition of Beta function]
=
Q 8:
B =
=
=
=
= [because ]
Q 9: Find the area of the surface generated by rotating the function about the x-axis over
and the curve
Solution: we have the equation of the form y=f(x) and we are rotating around the x-axis, we’ll use the formula
S =
We will calculate and then substitute it back into the equation
S =
S =
Using u-substitution and setting u= and du=36x3dx,
We calculate
Plugging these values back into the integral we get,
S=
S =
S =
S =
By integration we get
S =
S =
We wil insert back for u, and we have u = 1+9x4, and then evaluate over the interval
S =
=
S = 2, 294.8 square units.
THEREFORE,
The surface area obtained by rotating y= x3 around the x-axis over the interval is S = 2, 294.8
Q 10: Find the volume generated by revolving the region bounded by y = x2 and the x-axis on [-2,3] about the x-axis
Solution: The volume(v) of the solid is
V =
=
=
=
V = 55
UNIT-1
Q 1: Solve the following improper Integral
Solution:
Given,
Q2: Solve the following improper Integral
Solution: Given,
Q3: Solve the following improper Integral
Solution: Given,
Q 4 : Solve the following improper Integral
Solution: Given,
Q 5: evaluate the integral
Solution: we use
Substituting a=2x
Hence,
=
=
=
=
Q 6: Evaluate the integral
Solution: we use the formula
=
= .
Q 7: f(B) = Solve the given function.
Solution: =
= [Recursive function for the gamma function]
= [Recursive formula for the gamma function]
=
= [By the definition of Beta function]
=
Q 8:
B =
=
=
=
= [because ]
Q 9: Find the area of the surface generated by rotating the function about the x-axis over
and the curve
Solution: we have the equation of the form y=f(x) and we are rotating around the x-axis, we’ll use the formula
S =
We will calculate and then substitute it back into the equation
S =
S =
Using u-substitution and setting u= and du=36x3dx,
We calculate
Plugging these values back into the integral we get,
S=
S =
S =
S =
By integration we get
S =
S =
We wil insert back for u, and we have u = 1+9x4, and then evaluate over the interval
S =
=
S = 2, 294.8 square units.
THEREFORE,
The surface area obtained by rotating y= x3 around the x-axis over the interval is S = 2, 294.8
Q 10: Find the volume generated by revolving the region bounded by y = x2 and the x-axis on [-2,3] about the x-axis
Solution: The volume(v) of the solid is
V =
=
=
=
V = 55