Module-1
Laplace Transform
Question-1: Define Laplace transform and its conditions for existence.
Sol.
Let f(t) be any function of t defined for all positive values of t. Then the Laplace transform of the function f(t) is defined as-
Provided that the integral exists, here ‘s’ is the parameter that could be real or complex.
The inverse of the Laplace transform can be defined as below-
Here
f(t) is called the inverse Laplace transform of
L is called the Laplace transformation operator.
Conditions for the existence of Laplace transform-
The Laplace transform of f(t) exists for s>a, if
1. f(t) is a continuous function.
2. is finite
Question-2: Find the Laplace transform of the following function-
Sol.
Here
So that we can write it as-
Now-
Question-3: Find the Laplace transform of (1 + cos 2t)
Sol.
So that-
Question-4: define the first shifting property of Laplace transform
Sol.
(Theorem)- If
Proof: By definition-
Let (s – a) = r
Hence proved.
Question-5: Find the Laplace transform of
Sol. Here-
So that-
As we know that-
So that-
Hence-
Question-6: Find the Laplace transform of the following function-
Sol. The given function f(t) can be written as-
So, by definition,
Question-7: Find the Laplace transform of .
Sol. Here-
Now-
Question-8: using Laplace transform find the solution to the following initial value problem-
y’ + y =
Sol. On taking the Laplace transform and using the initial conditions, we get-
Thus
On breaking into partial fractions, we get-
Question-9: Express the function given below in terms of a unit step function and find it's Laplace transform as well-
Sol. Here we are given-
So that-
Question-10: Evaluate-
1.
Sol.1. As we know that-
So that-
2. As we know that-
Question-11: Find the inverse Laplace transform of-
Sol.
Question-12: Find
Sol.
Question-13: Use Laplace transform method to solve the following equation-
Sol. Here we have-
Take Laplace transform of both sides, we get-
It becomes-
(
So that-
Now breaking it into partial fractions-
We get the following results on inversion-
Question-14: solve the following differential equation by using Laplace transform-
Here D = d/dt and
Sol.
Here we have-
Now multiply (1) by D+1 and (2) by D – 1 we get-
Now subtract (4) from (3), we get-
By taking Laplace to transform we get-
Put the value of in (1) we get-
By taking Laplace to transform we get-
Which is the required answer.
Module-1
Laplace Transform
Question-1: Define Laplace transform and its conditions for existence.
Sol.
Let f(t) be any function of t defined for all positive values of t. Then the Laplace transform of the function f(t) is defined as-
Provided that the integral exists, here ‘s’ is the parameter that could be real or complex.
The inverse of the Laplace transform can be defined as below-
Here
f(t) is called the inverse Laplace transform of
L is called the Laplace transformation operator.
Conditions for the existence of Laplace transform-
The Laplace transform of f(t) exists for s>a, if
1. f(t) is a continuous function.
2. is finite
Question-2: Find the Laplace transform of the following function-
Sol.
Here
So that we can write it as-
Now-
Question-3: Find the Laplace transform of (1 + cos 2t)
Sol.
So that-
Question-4: define the first shifting property of Laplace transform
Sol.
(Theorem)- If
Proof: By definition-
Let (s – a) = r
Hence proved.
Question-5: Find the Laplace transform of
Sol. Here-
So that-
As we know that-
So that-
Hence-
Question-6: Find the Laplace transform of the following function-
Sol. The given function f(t) can be written as-
So, by definition,
Question-7: Find the Laplace transform of .
Sol. Here-
Now-
Question-8: using Laplace transform find the solution to the following initial value problem-
y’ + y =
Sol. On taking the Laplace transform and using the initial conditions, we get-
Thus
On breaking into partial fractions, we get-
Question-9: Express the function given below in terms of a unit step function and find it's Laplace transform as well-
Sol. Here we are given-
So that-
Question-10: Evaluate-
1.
Sol.1. As we know that-
So that-
2. As we know that-
Question-11: Find the inverse Laplace transform of-
Sol.
Question-12: Find
Sol.
Question-13: Use Laplace transform method to solve the following equation-
Sol. Here we have-
Take Laplace transform of both sides, we get-
It becomes-
(
So that-
Now breaking it into partial fractions-
We get the following results on inversion-
Question-14: solve the following differential equation by using Laplace transform-
Here D = d/dt and
Sol.
Here we have-
Now multiply (1) by D+1 and (2) by D – 1 we get-
Now subtract (4) from (3), we get-
By taking Laplace to transform we get-
Put the value of in (1) we get-
By taking Laplace to transform we get-
Which is the required answer.
Module-1
Module-1
Laplace Transform
Question-1: Define Laplace transform and its conditions for existence.
Sol.
Let f(t) be any function of t defined for all positive values of t. Then the Laplace transform of the function f(t) is defined as-
Provided that the integral exists, here ‘s’ is the parameter that could be real or complex.
The inverse of the Laplace transform can be defined as below-
Here
f(t) is called the inverse Laplace transform of
L is called the Laplace transformation operator.
Conditions for the existence of Laplace transform-
The Laplace transform of f(t) exists for s>a, if
1. f(t) is a continuous function.
2. is finite
Question-2: Find the Laplace transform of the following function-
Sol.
Here
So that we can write it as-
Now-
Question-3: Find the Laplace transform of (1 + cos 2t)
Sol.
So that-
Question-4: define the first shifting property of Laplace transform
Sol.
(Theorem)- If
Proof: By definition-
Let (s – a) = r
Hence proved.
Question-5: Find the Laplace transform of
Sol. Here-
So that-
As we know that-
So that-
Hence-
Question-6: Find the Laplace transform of the following function-
Sol. The given function f(t) can be written as-
So, by definition,
Question-7: Find the Laplace transform of .
Sol. Here-
Now-
Question-8: using Laplace transform find the solution to the following initial value problem-
y’ + y =
Sol. On taking the Laplace transform and using the initial conditions, we get-
Thus
On breaking into partial fractions, we get-
Question-9: Express the function given below in terms of a unit step function and find it's Laplace transform as well-
Sol. Here we are given-
So that-
Question-10: Evaluate-
1.
Sol.1. As we know that-
So that-
2. As we know that-
Question-11: Find the inverse Laplace transform of-
Sol.
Question-12: Find
Sol.
Question-13: Use Laplace transform method to solve the following equation-
Sol. Here we have-
Take Laplace transform of both sides, we get-
It becomes-
(
So that-
Now breaking it into partial fractions-
We get the following results on inversion-
Question-14: solve the following differential equation by using Laplace transform-
Here D = d/dt and
Sol.
Here we have-
Now multiply (1) by D+1 and (2) by D – 1 we get-
Now subtract (4) from (3), we get-
By taking Laplace to transform we get-
Put the value of in (1) we get-
By taking Laplace to transform we get-
Which is the required answer.