Question Bank ( unit-2)
Question Bank ( unit-2)
Question Bank ( unit-2)
Question-1: find the linear transformation of the matrix A.
A =
Sol. We have,
A =
Multiply the matrix by vector x = (x , y , z) , we get
Ax =
= ( )
f(x , y , z) = ( )
Which is the linear transformation of A.
Question-2: Are the vectors , , linearly dependent. If so, express x1 as a linear combination of the others.
Solution:
Consider a vector equation,
i.e.
Which can be written in matrix form as,
Here & no. Of unknown 3. Hence the system has infinite solutions. Now rewrite the questions as,
Put
and
Thus
i.e.
i.e.
Since F11 k2, k3 not all zero. Hence are linearly dependent.
Question-3: At what value of P the following vectors are linearly independent.
Solution:
Consider the vector equation.
i.e.
This is a homogeneous system of three equations in 3 unknowns and has a unique trivial solution.
If and only if Determinant of coefficient matrix is non zero.
consider .
.
i.e.
Thus for the system has only trivial solution and Hence the vectors are linearly independent.
Question-4: Determine the eigen values of eigen vector of the matrix.
Solution:
Consider the characteristic equation as,
i.e.
i.e.
i.e.
Which is the required characteristic equation.
are the required eigen values.
Now consider the equation
… (1)
Case I:
If Equation (1)becomes
R1 + R2
Thus
independent variable.
Now rewrite equation as,
Put x3 = t
&
Thus .
Is the eigen vector corresponding to .
Case II:
If equation (1) becomes,
Here
independent variables
Now rewrite the equations as,
Put
&
.
Is the eigen vector corresponding to .
Case III:
If equation (1) becomes,
Here rank of
independent variable.
Now rewrite the equations as,
Put
Thus .
Is the eigen vector for .
Question-5: : Diagonalise the matrix
Sol.
Let A=
The three Eigen vectors obtained are (-1,1,0), (-1,0,1) and (3,3,3) corresponding to Eigen values .
Then and
Also we know that
Question-6: Diagonalise the matrix
Sol.
Let A =
The Eigen vectors are (4,1),(1,-1) corresponding to Eigen values .
Then and also
Also we know that
Question-7: Find the characteristic equation of the matrix A = and Verify cayley-Hamlton theorem.
Sol. Characteristic equation of the matrix, we can be find as follows-
Which is,
( 2 - , which gives
According to cayley-Hamilton theorem,
…………(1)
Now we will verify equation (1),
Put the required values in equation (1) , we get
Hence the cayley-Hamilton theorem is verified.
Question-8: Find the characteristic equation of the the matrix A and verify Cayley-Hamilton theorem as well.
A =
Sol. Characteristic equation will be-
= 0
( 7 -
(7-
(7-
Which gives,
Or
According to cayley-Hamilton theorem,
…………………….(1)
In order to verify cayley-Hamilton theorem , we will find the values of
So that,
Now
Put these values in equation(1), we get
= 0
Hence the cayley-hamilton theorem is verified.
Question-9: Find the inverse of matrix A by using Cayley-Hamilton theorem.
A =
Sol. The characteristic equation will be,
|A - | = 0
Which gives,
(4-
According to Cayley-Hamilton theorem,
Multiplying by
That means
On solving ,
11
=
=
So that,
Question-10: Find the inverse of matrix A by using Cayley-Hamilton theorem.
A =
Sol. The characteristic equation will be,
|A - | = 0
=
= (2-
= (2 -
=
That is,
Or
We know that by Cayley-Hamilton theorem,
…………………….(1)t,
Multiply equation(1) by , we get
Or
Now we will find
=
=
Hence the inverse of matrix A is,
Question-11: : Find of matrix A by using Cayley-Hamilton theorem.
Sol. First we will find out the characteristic equation of matrix A,
|A - | = 0
We get,
Which gives,
(
We get,
Or I ……………………..(1)
In order to find find we take cube of eq. (1)
We get,
729I we know that-
729 we know that- value of I =
Question-12: find out the quadratic form of following matrix.
A =
Solution: Quadratic form is,
X’ AX
Which is the quadratic form of a matrix.
Question-13: find the real matrix of the following quadratic form:
Sol. Here we will compare the coefficients with the standard quadratic equation,
We get,
Question-14: Find the orthogonal canonical form of the quadratic form.
5
Sol. The matrix form of this quadratic equation can be written as,
A =
We can find the eigen values of A as –
|A - | = 0
= 0
Which gives,
The required orthogonal canonical reduction will be,
8 .