Unit-2
Transforms
Question-1: Using complex form find the Fourier series of the function f(x) = x2, defined on the interval [-1,1]
Solution:
Here the half-period is L=1.Therefore, the coefficient c0 is,
For n
Integrating by parts twice,we obtain
=
=
= .
= .
Question-2: Find the fourier integral representation of the function
Solution:
The graph of the function is shown in the below figure satisfies the hypothesis of
Theorem -1 . Hence from Eqn,(5) and (6), we have
Substituting these coefficients in Eqn.(4) we obtain
This is the Fourier integral representation of the given function.
Question-3: Find the Fourier integral representation of the function
Solution:
The graph of the given function is shown in the below figure . Clearly, the given function f(x) is an even function. We represent f(x) by the fourier cosine integral . We obtain
And thus ,
Question-4: Find the Fourier cosine integral of , where x>0, k>0 hence show that
Solution:
The Fourier cosine integral of f(x) is given by:
Question-5: Find the Fourier transform of
Sol. As we know that the Fourier transform of f(x) will be-
So that-
Now put
So that-
Question-6: Find the Fourier sine transform of
Sol. Here x being positive in the interval (0, ∞)
Fourier sine transform of will be-
Question-7: Find the Fourier sine transform of
Sol. Let
Then the Fourier sine transform will be-
Now suppose,
Differentiate both sides with respect to x, we get-
……. (1)
On integrating (1), we get-
Question-8: Find the Fourier transform of-
Hence evaluate
Sol. As we know that the Fourier transform of f(x) will be-
So that-
For s = 0, we get- F(s) = 2
Hence by the inverse formula, we get-
Putting x = 0, we get
So-
Question-9: Find the Fourier cosine transform of-
Sol. We know that the Fourier cosine transform of f(x)-
=
=
=
Question-10: Find Z-transform of the following functions-
(i)
(ii)
Sol.(i)
(ii)
Question-11:
Solution:
Long division method to obtain
2
Now x(z) can be written as,
X(z) = 2-
Question-12: Solve the differential equation by the z-transformation method.
Solution:
Given,
Let y(z) be the z-transform of
Taking z-transforms of both sides of eq(1) we get,
ie.
using the given condition,it reduces to
(z+1)y(z) =
Ie.
Y(z) =
Or Y(Z) =
On taking inverse Z-transforms, we obtain