Unit-1
Successive Differentiation and Mean Value Theorem
Question-1: If y = l , then show that-
Sol. We have,
y =
Differentiate y with respect to x, we get
=
Again diff. (n – 1) times w.r .t x , we get-
Question-2: Find the derivative of
Sol. Here we have-
Suppose, y =
First derivative-
Here ,
Let x =
So that
Which is the n’th derivative of the given function.
Question-3: Find cos x cos 2x cos 3x.
Sol.
So that-
n’th derivative-
Question-4: Find the derivative of the following function-
Sol. Partial fraction of the function y after splitting-
Suppose x – 1 = z, then
=
=
=
Here we can find its n’th derivative-
Question-5: Find if
Sol.
Here we have-
At x = 0,
When n is odd-
When n is even
Question-6: If y , then prove that-
Sol. Here it is given that-
On differentiating-
Or
= ny.2x
Differentiate again with respect to x, we get-
Or
…………………. (1)
Differentiate each term of (1) by using Leibnitz’s theorem, we get-
Therefore we get-
Hence proved.
Question-7: If , then prove that-
Sol. Here we have-
Or
Or
y = b cos[ n log(x/n)]
On differentiating, we get-
Which becomes-
Differentiate again both sides with respect to x, we get-
It becomes-
……………….. (1)
Differentiate each term n times with respect to x, we get-
Which is-
hence proved,
Question-8: If , then show that
Sol.
Also, find
Here
Differentiating with respect to x, we get
…(ii)
Squaring both side we get
…(iii)
Again differentiating with respect to x ,we get
Using Leibnitz’s theorem we get
…(iv)
Putting x=0 in equation (i),(ii) and (iii) we get
Putting n=1,2,3,4….
………………
Hence
Qustion-9: Verify Rolle’s theorem for the function f(x) = x2 for
Solution:
Here f(x) = x2;
i) Since f(x) is algebraic polynomial which is continuous in [-1, 1]
Ii) Consider f(x) = x2
Diff. w.r.t. x we get
f'(x) = 2x
Clearly f’(x) exists in (-1, 1) and does not becomes infinite.
Iii) Clearly
f(-1) = (-1)2 = 1
f(1) = (1)2 = 1
f(-1) = f(1).
Hence by Rolle ’s Theorem, there exist such that
f’(c) = 0
i.e. 2c = 0
c = 0
Thus such that
f'(c) = 0
Hence Rolle’s Theorem is verified.
Question-10: Verify the Lagrange’s mean value theorem for
Solution:
Here
i) Clearly f(x) = log x is logarithmic function. Hence it is continuous in [1, e]
Ii) Consider f(x) = log x.
Diff. w.r.t. x we get,
Clearly f’(x) exists for each value of & is finite.
Hence all conditions of LMVT are satisfied Hence at least
Such that
i.e.
i.e.
i.e.
i.e.
Since e = 2.7183
Clearly c = 1.7183
Hence LMVT is verified.
Questin-11: Verify Cauchy mean value theorems for &in
Solution:
Let &;
i) Clearly f(x) and g(x) both are trigonometric functions. Hence continuous in
Ii) Since &
Diff. w.r.t. x we get,
&
Clearly both f’(x) and g’(x) exist & finite in . Hence f(x) and g(x) is derivable in and
Iii)
Hence by Cauchy mean value theorem, there exist at least such that
i.e.
i.e. 1 = cot c
i.e.
Clearly
Hence Cauchy mean value theorem is verified.
Question-12: Verify Cauchy’s mean value theorem for the function f(x) = x⁴ and g(x) = x² in the interval [1,2]
Sol. We are given, f(x) = x⁴ and g(x) = x
Derivative of these fucntions ,
f’(x) = 4x³ and g’(x) = 2x
Put these values in Cauchy’s formula, we get
2c² =
c² =
c =
Now put the values of a = 1 and b = 2 ,we get
c = = = (approx..)
Hence the Cauchy’s theorem is verified.
Unit-1
Successive Differentiation and Mean Value Theorem
Question-1: If y = l , then show that-
Sol. We have,
y =
Differentiate y with respect to x, we get
=
Again diff. (n – 1) times w.r .t x , we get-
Question-2: Find the derivative of
Sol. Here we have-
Suppose, y =
First derivative-
Here ,
Let x =
So that
Which is the n’th derivative of the given function.
Question-3: Find cos x cos 2x cos 3x.
Sol.
So that-
n’th derivative-
Question-4: Find the derivative of the following function-
Sol. Partial fraction of the function y after splitting-
Suppose x – 1 = z, then
=
=
=
Here we can find its n’th derivative-
Question-5: Find if
Sol.
Here we have-
At x = 0,
When n is odd-
When n is even
Question-6: If y , then prove that-
Sol. Here it is given that-
On differentiating-
Or
= ny.2x
Differentiate again with respect to x, we get-
Or
…………………. (1)
Differentiate each term of (1) by using Leibnitz’s theorem, we get-
Therefore we get-
Hence proved.
Question-7: If , then prove that-
Sol. Here we have-
Or
Or
y = b cos[ n log(x/n)]
On differentiating, we get-
Which becomes-
Differentiate again both sides with respect to x, we get-
It becomes-
……………….. (1)
Differentiate each term n times with respect to x, we get-
Which is-
hence proved,
Question-8: If , then show that
Sol.
Also, find
Here
Differentiating with respect to x, we get
…(ii)
Squaring both side we get
…(iii)
Again differentiating with respect to x ,we get
Using Leibnitz’s theorem we get
…(iv)
Putting x=0 in equation (i),(ii) and (iii) we get
Putting n=1,2,3,4….
………………
Hence
Qustion-9: Verify Rolle’s theorem for the function f(x) = x2 for
Solution:
Here f(x) = x2;
i) Since f(x) is algebraic polynomial which is continuous in [-1, 1]
Ii) Consider f(x) = x2
Diff. w.r.t. x we get
f'(x) = 2x
Clearly f’(x) exists in (-1, 1) and does not becomes infinite.
Iii) Clearly
f(-1) = (-1)2 = 1
f(1) = (1)2 = 1
f(-1) = f(1).
Hence by Rolle ’s Theorem, there exist such that
f’(c) = 0
i.e. 2c = 0
c = 0
Thus such that
f'(c) = 0
Hence Rolle’s Theorem is verified.
Question-10: Verify the Lagrange’s mean value theorem for
Solution:
Here
i) Clearly f(x) = log x is logarithmic function. Hence it is continuous in [1, e]
Ii) Consider f(x) = log x.
Diff. w.r.t. x we get,
Clearly f’(x) exists for each value of & is finite.
Hence all conditions of LMVT are satisfied Hence at least
Such that
i.e.
i.e.
i.e.
i.e.
Since e = 2.7183
Clearly c = 1.7183
Hence LMVT is verified.
Questin-11: Verify Cauchy mean value theorems for &in
Solution:
Let &;
i) Clearly f(x) and g(x) both are trigonometric functions. Hence continuous in
Ii) Since &
Diff. w.r.t. x we get,
&
Clearly both f’(x) and g’(x) exist & finite in . Hence f(x) and g(x) is derivable in and
Iii)
Hence by Cauchy mean value theorem, there exist at least such that
i.e.
i.e. 1 = cot c
i.e.
Clearly
Hence Cauchy mean value theorem is verified.
Question-12: Verify Cauchy’s mean value theorem for the function f(x) = x⁴ and g(x) = x² in the interval [1,2]
Sol. We are given, f(x) = x⁴ and g(x) = x
Derivative of these fucntions ,
f’(x) = 4x³ and g’(x) = 2x
Put these values in Cauchy’s formula, we get
2c² =
c² =
c =
Now put the values of a = 1 and b = 2 ,we get
c = = = (approx..)
Hence the Cauchy’s theorem is verified.