Unit-2
Expansion of Functions and Indeterminate forms
Question-1: By using Maclaurin’s series expand tan x.
Sol.
Let-





Put these values in Maclaurin’s series we get-

Question-2: Expand by using Maclaurin’s series.
Sol.
Let





Put these values in Maclaurin’s series-

Or

Question-3: Prove that
Solution:
Let
Differentiate with respect to x,




Hence by Maclaurin’s Series,


Question-4: Expand by upto
.
Solution:
We have,



Question-5: Differentiate the function f(x) = by using the first principal method.
Sol.
We know that-

Here

Substituting ( for x gives-

Hence-


Question-6: Differentiate with respect to x-

Sol.
The given function can be written in the form

Now-

Question-:7 Expand in power of (x – 3)
Solution:
Let
Here a = 3
Now by Taylor’s series expansion,
… (1)










equation (1) becomes.


Question-8: Using Taylors series method expand in powers of (x + 2)
Solution:
Here
a = -2
By Taylors series,
… (1)
Since









,
, …..
Thus equation (1) becomes


Question-9: Expand in powers of x using Taylor’s theorem,
Solution:
Here


i.e.
Here
h = 2
By Taylors series
… (1)
By equation (1)



Question-10: Evaluate .
Sol. Let f(x) = and g(x) =
.
Here we see that this is the indeterminate form of 0/0 at x = 0.
Now by using L’Hospital rule, we get-

=
=
= = 1
Question-11: Evaluate
Sol. We can see that this is an indeterminate form of type 0/0.
Apply L’Hospital’s rule, we get

But this is again an indeterminate form, so that we will again apply L’Hospital’s rule-
We get
=
Question-12: Evaluate
Sol. Apply L’Hospital rule as we can see that this is the form of
=
Note- In some cases like above example, we can not apply L’Hospital’s rule.
Unit-2
Expansion of Functions and Indeterminate forms
Question-1: By using Maclaurin’s series expand tan x.
Sol.
Let-





Put these values in Maclaurin’s series we get-

Question-2: Expand by using Maclaurin’s series.
Sol.
Let





Put these values in Maclaurin’s series-

Or

Question-3: Prove that
Solution:
Let
Differentiate with respect to x,




Hence by Maclaurin’s Series,


Question-4: Expand by upto
.
Solution:
We have,



Question-5: Differentiate the function f(x) = by using the first principal method.
Sol.
We know that-

Here

Substituting ( for x gives-

Hence-


Question-6: Differentiate with respect to x-

Sol.
The given function can be written in the form

Now-

Question-:7 Expand in power of (x – 3)
Solution:
Let
Here a = 3
Now by Taylor’s series expansion,
… (1)










equation (1) becomes.


Question-8: Using Taylors series method expand in powers of (x + 2)
Solution:
Here
a = -2
By Taylors series,
… (1)
Since









,
, …..
Thus equation (1) becomes


Question-9: Expand in powers of x using Taylor’s theorem,
Solution:
Here


i.e.
Here
h = 2
By Taylors series
… (1)
By equation (1)



Question-10: Evaluate .
Sol. Let f(x) = and g(x) =
.
Here we see that this is the indeterminate form of 0/0 at x = 0.
Now by using L’Hospital rule, we get-

=
=
= = 1
Question-11: Evaluate
Sol. We can see that this is an indeterminate form of type 0/0.
Apply L’Hospital’s rule, we get

But this is again an indeterminate form, so that we will again apply L’Hospital’s rule-
We get
=
Question-12: Evaluate
Sol. Apply L’Hospital rule as we can see that this is the form of
=
Note- In some cases like above example, we can not apply L’Hospital’s rule.