Unit-5
Vector Calculus
Q1) If and then find-
1.
2.
A1) 1. We know that-
2.
Q2) If , then show that
1.
2.
A2)
Suppose and
Now taking L.H.S,
Which is
Hence proved.
2.
So that
Q3) If then find grad f at the point (1,-2,-1).
A3)
Now grad f at (1 , -2, -1) will be-
Q4) If then prove that grad u , grad v and grad w are coplanar.
A4)
Here-
Now-
Apply
Which becomes zero.
So that we can say that grad u, grad v and grad w are coplanar vectors.
Q5) Show that-
1.
2.
A5) We know that-
2. We know that-
= 0
Q6) Prove that
Note- here is a constant vector and
A6) here and
So that
Now-
So that-
Q7) What is the curl of the vector field F= ( x +y +z ,x-y-z,)?
A7)
Curl F =
=
=
= (2y+1)i-(2x-1)j+(1-1)k
= (2y+1)i+(1-2x)j+0k
= (2y+1, 1-2x,0)
Q8) Find the curl of F = ()i +4zj +
A8)
Curl F=
=
=(0-4)i-(2x-0)j+(0+1)k
=(-4)i – (2x)j+1k
=(-4,-2x,1)
Q9) Find the directional derivatives of at the point P(1, 1, 1) in the direction of the line
A9) Here
Direction ratio of the line are 2, -2, 1
Now directions cosines of the line are-
Which are
Directional derivative in the direction of the line-
Q10) Prove that the vector field is irrotational and find its scalar potential.
A10) As we know that if then field is irrotational.
So that-
So that the field is irrotational and the vector F can be expressed as the gradient of a scalar potential,
That means-
Now-
………………… (1)
……………………. (2)
Integrating (1) with respect to x, keep ‘y’ as constant-
We get-
…………….. (3)
Integrating (1) with respect to y, keep ‘x’ as constant-
We get-
…………….. (4)
Equating (3) and (4)-
and
So that-
Q11) Show that the vector field is irrotational and find the scalar potential function.
A11) Now for irrotational field we need prove-
So that-
So that the vector field is irrotational.
Now in order to find the scalar potential function-
Q12) Evaluate where = (2xy +z2) I +x2j +3xz2 k along the curve x=t, y=t2, z= t3 from (0,0,0) to (1,1,1).
A12) F x dr =
Put x=t, y=t2, z= t3
Dx=dt ,dy=2tdt, dz=3t2dt.
F x dr =
=(3t4-6t8) dt i – ( 6t5+3t8 -3t7) dt j +( 4t4+2t7-t2)dt k
=t4-6t3)dti –(6t5+3t8-3t7)dt j+(4t4 + 2t7 – t2)dt k
=
=+
Q13) Evaluate , where S is the surface of the sphere in the first octant.
A13) Here-
Which becomes-
Q14) Evaluate if V is the region in the first octant bounded by and the plane x = 2 and .
A14)
x varies from 0 to 2
The volume will be-
Q15) Apply Green’s theorem to evaluate where C is the boundary of the area enclosed by the x-axis and the upper half of circle
A15) We know that by Green’s theorem-
And it it given that-
Now comparing the given integral-
P = and Q =
Now-
and
So that by Green’s theorem, we have the following integral-
Q16) Verify green’s theorem in xy-plane for where C is the boundary of the region enclosed by
A16)
On comparing with green’s theorem,
We get-
P = and Q =
and
By using Green’s theorem-
………….. (1)
And left hand side=
………….. (2)
Now,
Along
Along
Put these values in (2), we get-
L.H.S. = 1 – 1 = 0
So that the Green’s theorem is verified.
Q17) 2 Show that
A17)
By divergence theorem, ..…(1)
Comparing this with the given problem let
Hence, by (1)
………….(2)
Now ,
Hence, from (2), We get,
Q18) Verify stoke’s theorem when and surface S is the part of sphere , above the xy-plane.
A18)
We know that by stoke’s theorem,
Here C is the unit circle-
So that-
Now again on the unit circle C, z = 0
Dz = 0
Suppose,
And
Now
……………… (1)
Now-
Curl
Using spherical polar coordinates-
………………… (2)
From equation (1) and (2), stoke’s theorem is verified.