Unit - 5
Expansion of Functions and Indeterminate forms
Question and answer
Then

Proof:-
Here f(x) = sin hx.
By Maclaurin’s expansion,
(1)
By equation (1) we get,


2. . Then

Proof:-
Here f(x) = cos hx
By Maclaurin’s expansion
(1)
By equation (1)


3. f(x) = tan hx

Proof:
Here f(x) = tan hx
By Maclaurin’s series expansion,
… (1)















By equation (1)


4. then

Proof:-
Here f(x) = log (1 + x)
By Maclaurin’s series expansion,
… (1)
By equation (1)


5.
Solution:
Here f(x) = log (1 + sin x)
By Maclaurin’s Theorem,
… (1)





……..
equation (1) becomes,


6. Expand in power of (x – 3)
Solution:
Let
Here a = 3
Now by Taylor’s series expansion,
… (1)










equation (1) becomes.


7. Using Taylors series method expand
in powers of (x + 2)
Solution:
Here
a = -2
By Taylors series,
… (1)
Since









,
, …..
Thus equation (1) becomes


8. Expand in ascending powers of x.
Solution:
Here

i.e.

Here h = -2
By Taylors series,
… (1)










equation (1) becomes,


Thus


9. Expand in powers of x using Taylor’s theorem,
Solution:
Here


i.e.
Here
h = 2
By Taylors series
… (1)
By equation (1)



10. Evaluate
Solution:
Let
…
By L – Hospital rule

