Unit - 5
Expansion of Functions and Indeterminate forms
Question and answer
- Then
Proof:-
Here f(x) = sin hx.
By Maclaurin’s expansion,
(1)
By equation (1) we get,
2. . Then
Proof:-
Here f(x) = cos hx
By Maclaurin’s expansion
(1)
By equation (1)
3. f(x) = tan hx
Proof:
Here f(x) = tan hx
By Maclaurin’s series expansion,
… (1)
By equation (1)
4. then
Proof:-
Here f(x) = log (1 + x)
By Maclaurin’s series expansion,
… (1)
By equation (1)
5.
Solution:
Here f(x) = log (1 + sin x)
By Maclaurin’s Theorem,
… (1)
……..
equation (1) becomes,
6. Expand in power of (x – 3)
Solution:
Let
Here a = 3
Now by Taylor’s series expansion,
… (1)
equation (1) becomes.
7. Using Taylors series method expand
in powers of (x + 2)
Solution:
Here
a = -2
By Taylors series,
… (1)
Since
,, …..
Thus equation (1) becomes
8. Expand in ascending powers of x.
Solution:
Here
i.e.
Here h = -2
By Taylors series,
… (1)
equation (1) becomes,
Thus
9. Expand in powers of x using Taylor’s theorem,
Solution:
Here
i.e.
Here
h = 2
By Taylors series
… (1)
By equation (1)
10. Evaluate
Solution:
Let
…
By L – Hospital rule