undefined | unit 4 programming 2

MICRO

UNIT - 4Programming – 2 Q1) write a procedure named Square that squares the contents of BL and places the result in BX. A1)Square: PUSH AX MOV AL, BL MUL BL MOV BX, AX POP AX RET Q2) write a program that computes y = (AL)2 + (AH)2 + (DL)2 places the result in CX. Make use of the SQUARE subroutine defined in the previous example. A2) MOV CX, 0000H MOV BL, AL CALL Square ADD CX, BX MOV BL, AH CALL Square ADD CX, BX MOV BL, DL CALL Square ADD CX, BX HLT Q3) Write a program to move a block of 100 consecutive bytes of data starting at offset address 400H in memory to another block of memory locations starting at offset address 600H. Assume both block at the same data segment F000H. A3)MOV AX, F000H MOV DS, AX MOV SI, 0400H MOV DI, 0600H MOV CX, 64H NEXTPT: MOV AH, [SI] MOV [DI], AH INC SI INC DI LOOP NEXTPT HLT Q4) Using string operation, implement the previous example to copy block of memory to another location. A4) MOV CX, 64H MOV AX, F000H MOV DS, AX MOV ES, AX MOV SI, 400H MOV DI, 600H CLD NXTPT: MOVSB LOOP NXTPT HTL Q5) Write a program loads the block of memory locations from A000H through 0A00FH with number 5H.A5)MOV AX, 0H MOV DS, AX MOV ES, AX MOV AL, 05 MOV DI, 0A000H MOV CX, 0FH CLD AGAIN: STOSB LOOP AGAIN Q6) Write an ALP for reading and displaying a character.A6)

LABEL	CODE	COMMENT
	MOV AH, 1H	keyboard input subprogram
	INT 21H	character input
		character is stored in AL
	MOV C, AL	copy character from AL to C

Q7)Write an ALP to add subtract multiply and divide two numbers.A7)

LABEL	CODE	COMMENT
	ORG0000H
	MOV DX, #07H	move the value 7 to the register AX
	MOV AX, #09H	move the value 9 to accumulator AX
	ADD AX, 00H	add CX value with R0 value and stores the result in AX

	ORG5000H
	MOV BX, #07H	move the value 7 to the register BX
	MOV DX, #09H	move the value 9 to accumulator DX
	MUL DX, 00H	Multiply DX value with R0 value and stores the result in DX

	ORG8000H
	MOV BX, #07H	move the value 7 to the register BX
	MOV AX, #08H	move the value 8 to accumulator AX
	SUBB AX, 09H	Result value is stored in the Accumulator AX

	ORG2000H
	MOV BX, #07H	move the value 7 to the register BX
	MOV AX, #18H	move the value 18 to accumulator AX
	DIV AX, 09H	Final value is stored in the Accumulator AX
	HLT

Q8) Write an ALP to divide a 16 bit number by an 8 bit number.A8)

LABEL	CODE	COMMENT
	MOV SI, 600	assigns 600 to SI
	MOV DI, 500	assigns 500 to DI
	MOV BL, [SI]	moves the content of [SI] to BL register i.e. value of divisor will be stored in BL
	INC SI	increment the content of SI by 1
	MOV AX, [SI]	moves the content of [SI] and [SI + 1] to AX register i.e. value of dividend will be stored in AX
	DIV BL	divide the content of AX by BL, after execution of this instruction the quotient get stored in AL and remainder in AH
	MOV [DI], AX	moves the content of AX to [DI]
	HLT	stops the execution of program

Q9) Write an ALP to find the factorial of a number. A9)

LABEL	CODE	COMMENT
	MOV CX, [5000]	loads 5000 Memory location content to CX Register
	MOV AX, 0001	loads AX register with 0001
	MOV DX, 0000	loads DX register with 0000
	MUL CX	multiply AX with CX and store result in DX:AX pair
	LOOP 040A	runs loop till CX not equal to Zero
	MOV [6000], AX	store AX register content to memory location 6000
	MOV [6001], DX	store DX register content to memory location 6001
	HLT	stops the execution of program

Q10) Write an ALP to find the highest among the given numbers.A10)

LABEL	CODE	COMMENT
DATA	DB 50,44,80,98,42	12H, 2CH, 50H, 62H, 2AH
	MOV CX, 5	Set up loop counter
	MOV BX, OFFSET DATA	BX points to the given data
	SUB AL, AL	AL holds the highest number found till now
AGAIN	CMP AL, [BX]	Compare the next number
	JA NEXT	Jump if AL is still the highest
	MOV AL, [BX]	Else hold the new number
NEXT	INC BX	Points the next number
	LOOP AGAIN	Continue to search
	HLT	stops the execution of program

Q11) Write an ALP to reverse a 16 bit number. A11)

LABEL	CODE	COMMENT
	MOV AL, [3050]	loads contents of memory location 3050 in AL
	MOV AH, [3051]	loads contents of memory location 3051 in AH
	MOV CX, 0004	assign 0004 to CX register pair
	ROL AL, CX	rotate the content of AL register left by 4 bits i.e. value of CX register pair
	ROL AH, CX	rotate the content of AH register left by 4 bits i.e. value of CX register pair
	MOV [3050], AH	stores the content of AH in 3050 memory address
	MOV [3051], AL	stores the content of AL in 3051 memory address
	HLT	stops the execution of program

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