AOL (f) = V0/Vin if Vf = 0 ----- (1) where AOL (f) = open loop volt gains. The closed loop gain Af is given by AF = V0/Vin = AOL / (1+(AOL) (B) ----(2) B = gain of feedback circuit. B is a constant if the feedback circuit uses only resistive components. |
GBP = Gain x Bandwidth = A x BW For example, from the graph above the gain of the amplifier at 100kHz is given as 20dB or 10, then the gain bandwidth product is calculated as: GBP = A x BW = 10 x 100,000Hz = 1,000,000. Similarly, the operational amplifiers gain at 1kHz = 60dB or 1000, therefore the GBP is given as: GBP = A x BW = 1,000 x 1,000Hz = 1,000,000. The Voltage Gain (AV) of the operational amplifier can be found using the following formula: Av = Vout/ Vin and in Decibels or (dB) is given as: 20 log (A) or 20 log (Vout/ Vin ) in dB |
Using the formula 20 log (A), we can calculate the bandwidth of the amplifier as: 37 = 20 log (A) therefore, A = anti-log (37 /20) = 70.8 GBP/ A = Bandwidth, therefore, 1,000,000 / 70.8 = 14,124Hz, or 14kHz Then the bandwidth of the amplifier at a gain of 40dB is given as 14kHz as previously predicted from the graph. |
= When R4 is considered the feedback factor in the circuit becomes The gain of op-amp is The voltage gains for inverting amplifier is Without R4 and C4 the gain of amplifier is Av = 1/. With R4 and C4, ’>. The compensating components are actually selected according to higher gain which increases the bandwidth. As R4 and C4 are present the input impedance of op-amp is modified and this is the reason it is called as Zin Mod compensation. The value of Zin is given as |